如果cur的下两个节点都存在, 并且两个节点的值都相同, 则开始删除和cur.next值相同的节点, 否则cur向前一步 @param head @return
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| class ListNode { int val; ListNode next; ListNode() {} ListNode(int val) { this.val = val; } ListNode(int val, ListNode next) { this.val = val; this.next = next; } }
class Solution {
public ListNode deleteDuplicates(ListNode head) { ListNode dummy = new ListNode(-1000, head); ListNode cur = dummy; while (cur.next != null && cur.next.next != null) { int val = cur.next.val; if (cur.next.next.val == val) { while (cur.next != null && cur.next.val == val) { cur.next = cur.next.next; } } else { cur = cur.next; } } return dummy.next; } }
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